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X^2+14X+49=576
We move all terms to the left:
X^2+14X+49-(576)=0
We add all the numbers together, and all the variables
X^2+14X-527=0
a = 1; b = 14; c = -527;
Δ = b2-4ac
Δ = 142-4·1·(-527)
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2304}=48$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-48}{2*1}=\frac{-62}{2} =-31 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+48}{2*1}=\frac{34}{2} =17 $
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